• kdb+

  How to make two referencing sub-projection works?

  Posted by vivo on July 29, 2022 at 12:00 am

  I have below code, which doesn’t work. h and g are 2 projections defined inside f, and they are referencing to each other.

  Theorectically, the answer should be:

  f[10]=g[10]

  =h[8] + 20

  =g[5] + 30 + 20

  =h[3] + 20 + 30 + 20

  =g[0] + 30 + 20 + 30 + 20

  =h[-2] +20 + 30 + 20 + 30 + 20

  = -2 + 120 = 118

  f:{[xF]
   g:{[h;xG] $[xG < 0; xG; h[xG - 2] + 20]}[h]; // doesn't work, as h is not yet defined
   h:{[g;xH] $[xH < 0; xH; g[xH - 3] + 30]}[g];
   g[xF]
   };
  f[10];

  How to make it works?

  vivo replied 8 months, 1 week ago 2 Members · 1 Reply
• 1 Reply

• 

  kshepherd

  Member

  July 29, 2022 at 12:00 am

  f:{[xF] 
      g:{[h;xG] $[xG < 0; xG; h[.z.s; xG - 2] + 20]}; 
      h:{[g;xH] $[xH < 0; xH; g[.z.s; xH - 3] + 30]}; 
      g[h; xF] }; 
  f[10];

  Another option is to use .z.s to refer to the calling function when calling the other function.

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