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KDB Geom/Trig
Hey All,
How do you use KDB sin/cos/tan to solve for the angles of a triangle?
Im not asking about SOHCAHTOA — when I use the sin/cos/tan functions in KDB/q I get different results compared to other language’s functions.
Is there a conversion im missing?
Thanks!
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3 Replies
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Hi planefan,
Thanks for posting your query on KX Community!
For the angles you are trying to solve, are you working in degrees or radians?
KDB assumes a radian input, see here using sin as an example. You can see how to convert between degrees and radians on Geometry and trigonometry
Kind regards,
David
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Hey David, thanks for the help!
I’m dealing in degrees, or trying to.
Does kdb sin/cos only accept radians?
For example, if I go sin(30) on my comp calc i get .5. When I go sin(30) in kdb I get -0.9880316.
At it’s simplest form, I’m trying to use the sin/cos/tan functions within KDB similar to how i’d use them on my graphing calculator.
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Hi planefan,
Radians tend to be the more natural unit when working with angles than degrees, and you’ll find they are typically the default unit in most languages.
KDB doesn’t have built in support for degrees, however you can work in degrees by converting to radians and rounding your results.
For example:
q)deg:0,0+12#30 q)deg 0 30 60 90 120 150 180 210 240 270 300 330 360 q)pi:3.141592653589793 q)round:{(10 xexp neg x)*`long$y*10 xexp x}[3;] /3 dp; change as necessary q)deg!round sin deg*pi%180 0 | 0 30 | 0.5 60 | 0.866 90 | 1 120| 0.866 150| 0.5 180| 0 210| -0.5 240| -0.866 270| -1 300| -0.866 330| -0.5 360| 0You can set the above as a function for easier re-use; and also swap sin, for cos or tan, although be careful with tan(90) and tan(270) which should be be set to null / undefined.
Kind regards,
David
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