• KX Academy

  like comparison

  Posted by lestat-jin on April 3, 2024 at 3:42 pm

  Hi:

   

  not sure why for the below two like comparison, the first one returns 1 and second type error? given both are comparing a symbol on the left to its equivalent in string.

   

  `IBM like "IBM" 
  `t like "t"

   

  thanks,

  lestat-jin replied 7 months, 3 weeks ago 3 Members · 4 Replies
• 4 Replies

• 

  lestat-jin

  Member

  April 3, 2024 at 3:43 pm

  it does not get shown properly but IBM and t should be symbol type,

• 

  pgyorok

  Member

  April 3, 2024 at 3:53 pm

  like takes a string on the right. “IBM” is a string. “t” is not a string but a character – this is a quirk in the syntax. If you want to have a one-character string you have to use enlist, in this case enlist”t”.

• 

  rocuinneagain

  Member

  April 3, 2024 at 3:57 pm

  q)type"t" // t is a character atom - 'like' expects a character vector 
  -10h 
  q)type"IBM" // IBM is a character vector 
  10h 
  q)type enlist "t" // You can enlist an atom to be a single item vector 
  10h 
  q)type (),"t" // (), is useful as a conditional enlist. It enlists the atom 
  10h 
  q)type (),"IBM" // It does not enlist the vector 
  10h

• 

  lestat-jin

  Member

  April 3, 2024 at 4:47 pm

  Thank you both!

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