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Hi @lestat-jin

The correct way to execute your answer would be to remove the square brackets:

{8>count x}{x,sum -2#x}\0 1

This is because we are looking for the dyadic form of the scan adverb ‘x f\y’. Which if I use a parse tree to explain, would look like this:

q)-5!"{8>count x}{x,sum -2#x}\\0 1" / the correct version
(\;{x,sum -2#x})       
{8>count x}            
0 1                    

However if you use square brackets after scan, it forces it into monadic scan form, ‘x[f\y]’:

q)-5!"{8>count x}{x,sum -2#x}\\[0 1]"
{8>count x}
((\;{x,sum -2#x});0 1)

If you have any questions on this, please let me know!

Thanks,

Megan