Re: Basic (but still intriguing to me) q Interpreter question

[cillianreilly]

Hi JP, this is just the underlying k implementation of idesc: https://code.kx.com/q/ref/desc/#idesc

 

q)a:0 1 1 0 -1 0 1 -1 0 0 
q)idesc 
k){$[0h>@x;'`rank;>x]} 
q)idesc[a]~(>)a 
1b 
q) >a 
1 2 6 0 3 5 8 9 4 7

 

The brackets allow q to interpret this, but the use is discouraged (https://code.kx.com/q/basics/exposed-infrastructure/#unary-forms). Rather use the idesc keyword instead.