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Precisely (removing the <count>), many thanks:-)
Funny, I dug into it this am and came up with {f/[x;1 2]}/[t], but didn’t think (still not super fluent in q) about using the projection in the lambda.
Again, thank you for your time and input.
JP
Precisely (removing the <count>), many thanks:-)
Funny, I dug into it this am and came up with {f/[x;1 2]}/[t], but didn’t think (still not super fluent in q) about using the projection in the lambda.
Again, thank you for your time and input.
JP
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