Re: Decimal Places by Condition

[Laura]

 

q)show val:.01 .0125 .01234568 .9999 .008 0.01 0.0125 0.01234568 0.9999 0.008 
q).001*floor .5+1000*val 
0.01 0.013 0.012 1 0.008

 

More generally, as a function which takes number of decimal places as its left argument:

 

q){%[;s]floor .5+y*s:10 xexp x}[3]val 
0.01 0.013 0.012 1 0.008

 

Slightly less obviously you can elide floor .5+ with a faster Cast:

 

q){%[;s]"i"$y*s:10 xexp x}[3]val 
0.01 0.013 0.012 1 0.008