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Home Forums kdb+ Double comma when converting qsql statements to functional statements Re: Double comma when converting qsql statements to functional statements

  • jason_fealy

    Member
    January 11, 2022 at 12:00 am

    The list of constraints (index 2) is itself a parse tree which means value cannot be applied to the output of parse. For a simple example like this, it’s just a matter of removing a level of nesting but just to illustrate….

    q)show t:([]a:1 2;b:10 20); 
    a b 
    ---- 
    1 10 2 20 
    q)show pt:parse"select from t where a>1"; 
    // parse tree at index 2 
    ? `t ,,(>;`a;1) 0b () 
    q)value pt // value cannot be applied 
    'type [0] value pt // value cannot be applied ^ 
    q)@[pt;2;eval] // evalute the parse tree at index 2 which removes a level of nesting 
    ? `t ,(>;`a;1) 0b () 
    q) 
    q)value @[pt;2;eval] // value can be applied to output 
    a b 
    ---- 
    2 20 
    q) 
    q)?[t;enlist(>;`a;1);0b;()] ~ value @[pt;2;eval] 
    // matches manually typed functional form 1b

     

    Some further reading which includes more complex examples https://code.kx.com/q/wp/parse-trees/