Re: Function composition using common argument

[cillianreilly]

You can do this using iteration over a list of the functions to apply.

q){z .(y;x)}[a]/[3;(f2;f1)] 
0n 0.5 0.5 0.3333333 0.25 0.2 0.1666667 0.1428571 0.125 0.1111111

Adding another function:

q)f3:+ 
q){z .(y;x)}[a]/[3;(f2;f1;f3)] 
0n 1.5 2.5 3.333333 4.25 5.2 6.166667 7.142857 8.125 9.111111