Re: Function return notation.

[Laura]

Two expressions: one multiplies 0+0 by 1%0&0; the other adds them.

The sum of two long zeros is long zero.

1%0 is float infinity 0w. The type of the right argument does not matter; Divide always returns a float.

So the comparison is between 0*0w and 0+0w.

The latter is 0w. Surely expected: infinity plus x is infinity.

The unexpected result then is 0*0w. Is not 0*x always zero? But here its a float null 0n. I do not know the mathematical justification for this; perhaps someone else can shed light?

BTW your lambdas could be simpler:

test1:{(x+y)*1%x&y} 
test2:{(x+y)+1%x&y}