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Hello @chan_chenyanj,
As we discussed previously regarding ‘1’, including ‘each’ here will return a rank error given that ‘iasc’ accepts a list as its argument and `3Y`5Y is a simple symbol list.
To elaborate on ‘2’, I believe you want to query an updated table created after running ‘1’, i.e., assign ‘1’ (without each)
‘2’ logic is erroneous. `@ needs to be replaced with ‘@. To explain the logic, it is determining whether or not the new columns have a null symbol, and if it does, then delete from the table.
Happy Coding,
Leah