Home › Forums › kdb+ › kdb equivalent of pandas groupby › Re: kdb equivalent of pandas groupby
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Hi powerpeanuts,
I would keep it simple as you have it, and change select to update in your example as follows:
q)update change:0^price-prev[price] by sym from trade time sym price size change ----------------------------------- 09:30:00.000 a 10.75 100 0 09:31:00.000 a 11.75 100 1 09:32:00.000 a 13.2 100 1.45 09:30:00.000 b 100.75 100 0 09:31:00.000 b 106.95 100 6.2 09:32:00.000 b 123.95 100 17
Note, I’ve also used fill (^) here to set the first change value for each sym as 0; this is optional and you can leave it as null if you prefer.
Hope this helps and answers your question.
Kind regards,
David