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Very nice !
Just to make your solution visually easier to read, I’ve casted to symbols:q)progression:`$("C";"C#";"D";"D#";"E";"F";"F#";"G";"G#";"A";"A#";"B") q)notes:flip progression mod[;12]til[13]+/:progression? q)notes `$'"EADGBE" E A D G B E F A# D# G# C F F# B E A C# F# G C F A# D G G# C# F# B D# G# A D G C E A A# D# G# C# F A# B E A D F# B C F A# D# G C C# F# B E G# C# D G C F A D D# G# C# F# A# D# E A D G B E
And to satisfy for a one-liner, condensed as:
{flip x mod[;12]til[13]+/:x?y}[`$(“C”;”C#”;”D”;”D#”;”E”;”F”;”F#”;”G”;”G#”;”A”;”A#”;”B”);`$'”EADGBE”]
Look forward to seeing how others approach this problem.