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Home › Forums › kdb+ › wavg implementation detail › Re: wavg implementation detail

  • lan

    Member
    September 6, 2021 at 12:00 am

    Hi Leah,

    Thanks for your explanation.

    So for the case “0 wavg x”, it is equivalent to (0*x)%0 => 0%0=0n. It really makes sense.

    Thank you and your team again.

     

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