Home › Forums › kdb+ › Why creating a table from a tale results in a list of dictionaries? › Re: Why creating a table from a tale results in a list of dictionaries?
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A non-keyed table is just a list of dictionaries, flipped:
q)tab:([]a:1 2 3;b:`a`b`c) tab a b --- 1 a 2 b 3 c q)`a`b!(1 2 3;`a`b`c) a| 1 2 3 b| a b c q)flip `a`b!(1 2 3;`a`b`c) a b --- 1 a 2 b 3 c q)tab~flip `a`b!(1 2 3;`a`b`c) 1b
What you are doing here is creating a new table, with a column called tab. This new column has a record for each row of the original table as a dictionary
q)tab:([]a:1 2 3;b:`a`b`c) tab a b --- 1 a 2 b 3 c q)([]tab) tab ----------- `a`b!(1;`a) `a`b!(2;`b) `a`b!(3;`c)
You can also enlist the table to create a single record in the new table:
q)([] enlist tab) tab -------------------- +`a`b!(1 2 3;`a`b`c)
If you want to create a table from a table, typically you would utilise query filtering to select a subset of columns, or joins from another table. What is your use case here?