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Basic (but still intriguing to me) q Interpreter question
A bit at lost here… Can someone enlighten me as to how the interpreter works in the following situation:
q)show a:10?(-1 0 1) //Just to have something
0 1 1 0 -1 0 1 -1 0 0q)(>)a //That’s the curiosity
1 2 6 0 3 5 8 9 4 7I understand this is actually the same as…
q)raze where each a=/:desc distinct a
1 2 6 0 3 5 8 9 4 7but… can’t figure out where this is coming from(!)
Thx in advance
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2 Replies
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Hi JP, this is just the underlying k implementation of idesc: https://code.kx.com/q/ref/desc/#idesc
q)a:0 1 1 0 -1 0 1 -1 0 0 q)idesc k){$[0h>@x;'`rank;>x]} q)idesc[a]~(>)a 1b q) >a 1 2 6 0 3 5 8 9 4 7The brackets allow q to interpret this, but the use is discouraged (https://code.kx.com/q/basics/exposed-infrastructure/#unary-forms). Rather use the idesc keyword instead.
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Feel ashamed(!)… I realize I shouldn’t have skipped that <k> part of the language:-)
Thx again
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