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Concatenation issue for atomic values
Posted by denakaran on October 6, 2021 at 12:00 amHi guys,
When i’m doing `$(“1″;”0”) it is automatically showing as “10”. Is there any way i can make it as `1`0
denakaran replied 8 months ago 2 Members · 6 Replies -
6 Replies
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You can use each-right to cast each character one at a time:
https://code.kx.com/q/ref/maps/#each-left-and-each-right
q) `$”10″
`10
q) `$/:”10″
`1`0
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Hey, thanks for your input here but to be more clear
if i’m having a table like this
t:([]Vals:`$(“1″;”0″;”10”))
if i’m passing the parameters as 1 and 0 means it should return 1 and 0 from table t. Also if i’m passing as 10 it should return as 10
Currently it is showing the results as 1 and 0 for both 1,0 and 10. Please check the attached screenshot
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All of these items are equivalent:
q)"10" "10" q)("1";"0") "10" q)("10") "10"
They all resolve to 2 item lists containing characters
https://code.kx.com/q/basics/datatypes/
Here are some more example queries which may help:
q)select from t where Vals in `$/:("1";"10") Vals ---- 1 10 q)select from t where Vals in `$/:("1";"0") Vals ---- 1 0 q)select from t where Vals in `$"10" Vals ---- 10 q)select from t where Vals in `$"1" Vals ---- 1
You can use ‘=’ rather than ‘in’ if you are searching for only one value:
q)select from t where Vals=`$"1" Vals ---- 1
You can input your symbols directly rather than casting:
q)`0`1`10 `0`1`10
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A single character .i.e “1” is a type -10h
A list of characters .i.e “10” is a type 10h
You can create a single character list using ‘enlist’ .i.eq)type each ("1";"0";"11-15") /Some are lists some are not -10 -10 10h q)type each (enlist "1";enlist "0";"11-15") /All are lists 10 10 10h q)("1";"0") "10" q)type each ("1";"0") -10 -10h q)(enlist "1";enlist "0") //Using enlist to make single character lists ,"1" ,"0" q)type each (enlist "1";enlist "0") 10 10h
Using ‘enlist’ will help prevent unwanted concatenation for you.
https://code.kx.com/q/ref/enlist/ -
Hi , in my case i’m giving a multiselect option which may pass 1 or 0 or 10 or 11-15 or Above 15 etc.. So that i’m facing this issue
`q))`$(“1″;”0″;”11-15”)
`1`0`11-15
q))`$(“1″;”0”)
`10
q))`$(“10”)
`10So user may select anything from the list together.
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Hey , this really helps. I used the type to see when the user selects multiple values.
q))type (“1″;”0”)
10h
q))type (“1″;”10”)
0hSo based on that i added the condition now which works fine for my scenario. Thanks a lot !!
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