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joining strings kdb+
why does joining these 2 strings give unexpected results?
-> system”pwd” = and the type is 0h as well
-> (system”pwd”),”/xyz.csv” //type of first string is 0h and type of “xyz.csv” is 10h as expected -
2 Replies
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https://code.kx.com/q/ref/system/ “returns the result as a list of character vectors.”
Returns a list (0h) of character vectors (10h).
q)type system”ls -l”
0h
q)count system”ls -l”
28
q)type system”pwd”
0h
q)count system”pwd”
1
q)first system”pwd”
“/Users/myuser”
q)type first system”pwd”
10h
q)(first system”pwd”),”/some”
“/Users/myuser/some”
code.kx.com
system is a q keyword that executes a system command.
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It’s joining a list (of lists) to another list (of characters)
q)(system"pwd"),"/xyz.csv" "/home/rocuinneagain" "/" "x" "y" "z" "." "c" "s" "v"
To join a list of lists to another list of lists add ‘enlist’
q)(system"pwd"),enlist "/xyz.csv" "/home/rocuinneagain" "/xyz.csv"
To add a list of characters to a list of characters use ‘first’
q)(first system"pwd"),"/xyz.csv" "/home/rocuinneagain/xyz.csv"
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