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like comparison
Hi:
not sure why for the below two like comparison, the first one returns 1 and second type error? given both are comparing a symbol on the left to its equivalent in string.
`IBM like "IBM" `t like "t"
thanks,
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4 Replies
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it does not get shown properly but IBM and t should be symbol type,
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like takes a string on the right. “IBM” is a string. “t” is not a string but a character – this is a quirk in the syntax. If you want to have a one-character string you have to use enlist, in this case enlist”t”.
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q)type"t" // t is a character atom - 'like' expects a character vector -10h q)type"IBM" // IBM is a character vector 10h q)type enlist "t" // You can enlist an atom to be a single item vector 10h q)type (),"t" // (), is useful as a conditional enlist. It enlists the atom 10h q)type (),"IBM" // It does not enlist the vector 10h
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Thank you both!
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