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terminating condition for iterators
not sure why the below does not work as it keeps causing crash in Jupyter Notebook?
{8>count x}{x,sum -2#x}\[0 1]
I understand the condition to terminate iteration can be placed inside function input, e.g. f[{condition};input] or {condition}f[input], for example this works as given in the notebook : {1000 > max x}{(+)prior x,0}\ 1
in general what is recommended ways to write conditions for terminating the “loop”/iteration ?
Thanks,
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2 Replies
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Hi @lestat-jin
The correct way to execute your answer would be to remove the square brackets:
{8>count x}{x,sum -2#x}\0 1This is because we are looking for the dyadic form of the scan adverb ‘x f\y’. Which if I use a parse tree to explain, would look like this:
q)-5!"{8>count x}{x,sum -2#x}\\0 1" / the correct version (\;{x,sum -2#x}) {8>count x} 0 1However if you use square brackets after scan, it forces it into monadic scan form, ‘x[f\y]’:
q)-5!"{8>count x}{x,sum -2#x}\\[0 1]" {8>count x} ((\;{x,sum -2#x});0 1)If you have any questions on this, please let me know!
Thanks,
Megan
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Thanks a lot. could you explain why dyadic function is expected here? what is the f in “x f\ y” here? the {8>count x}{x,sum -2#x}\0 1 only takes one argument which is x…
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