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I believe the confusion here is just based on the syntax, to the q interpreter ( 11 22 ), 11 22 or indeed ( 11; 22 ) all resolve to the same list, * being atomic is applied to each item.
To obtain your result vector of 11 154 you’d need to explicitly demarcate 11 from 12 either via parantheses as in
q) (11;22*3+4)
or via joining 11 to the result of 22*3+4
q) 11 , 22*3+4