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right to left evaluation
Hi, I’m new to q and array programming language. I’m having trouble understanding what it means to be right to left evaluation.
I was expecting the 2nd output should be 11 154 but this is not the case. I’m confused when the left operand of * operator can be list or atom. how does q determine when to stop? under what situation, q can treat 22*3+4 as one block and get 11 154?
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1 Reply
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I believe the confusion here is just based on the syntax, to the q interpreter ( 11 22 ), 11 22 or indeed ( 11; 22 ) all resolve to the same list, * being atomic is applied to each item.
To obtain your result vector of 11 154 you’d need to explicitly demarcate 11 from 12 either via parantheses as in
q) (11;22*3+4)
or via joining 11 to the result of 22*3+4
q) 11 , 22*3+4
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